If x^2+px+1 be a factor of (ax^3+bx+c),then show that (x^2+px+1) is also a factor of (cx^3+bx^2+a). (2024)

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Introduction Content

Introduction

If x^2+px+1 be a factor of (ax^3+bx+c),then show that (x^2+px+1) is also a factor of (cx^3+bx^2+a).

Content

Bismillahirrahmanirrahim on the demand of jayadev Sarma, a problem if X square plus px plus 1, we a factor of polynomial, ax, cube, plus BX plus C, then show that X square plus px plus 1 is also a factor of C X cube polynomial, C, X cube, plus BX, plus a Tom, a gibbet Rd again, a key is polynomial character.

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A k cancel reject a cake opening - bodega, meniscus c square except Alaska.

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Number two one on achillea a be operatic: the temple as body a people skip an minus chi square, plus cos e square all upon me, but we will see filemaker dating any a be compelling that a minus Chi square or plus Casey's Christmas absolution, leading upon me a square, a X, minus K or yamaraja Larry Mendte equals L dagger.

They prove cardiac in remainder, zero, a dou X square plus px, plus one you had given Paul in America factor over yo me broken away.

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He will be 0 paper over a equation number to say the city cases you Romeo multiply going into a be 0, ub 0 or you don't go DIF V, 0, Oh Maura.

You remainder, the remainder that was 0.

Remainder remainder, 0, cube robber against the M Casselton.

Any therefore X square, minus px, plus 1 is a factor factor of given polynomial C X cube, plus B X square plus a a maple popcorn, and thank you very much indeed for listening me.

Radovan alhamdulillahi rabbil aalameen.

If x^2+px+1 be a factor of (ax^3+bx+c),then show that (x^2+px+1) is also a factor of (cx^3+bx^2+a). (2024)
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